Write out the formula V AC /β (2) and replace V AC with the AC voltage you found with your multimeter. Use a calculator to solve your equation if you want the most precise answer. [3] For example, if the AC power source has 120 V, then your formula would be 120/β (2) = 84.85 V in a DC signal.
In an AC circuit, the voltage would appear to rise and fall at the frequency of the circuit (most likely 50 or 60 Hz). Measuring this quantity on a DC voltage setting would attempt to display the instantaneous voltage at every measurement. Since itβs changing, the displayed voltage would also seem to be jumping around constantly.
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